If the current through a resistor doubles, the voltage across it changes how?

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Multiple Choice

If the current through a resistor doubles, the voltage across it changes how?

Doubling the current through a resistor with the same resistance doubles the voltage across it. This follows Ohm’s law: V = I × R. If R is constant and I becomes 2I, then V becomes 2I × R = 2(V), so the voltage doubles. (As a bonus, the power dissipated would rise by a factor of four, since P = I^2R.) Halving the current, quadrupling it, or leaving the voltage unchanged would require different changes to either the current or the resistance, which isn’t the scenario here.

Doubling the current through a resistor with the same resistance doubles the voltage across it. This follows Ohm’s law: V = I × R. If R is constant and I becomes 2I, then V becomes 2I × R = 2(V), so the voltage doubles. (As a bonus, the power dissipated would rise by a factor of four, since P = I^2R.)

Halving the current, quadrupling it, or leaving the voltage unchanged would require different changes to either the current or the resistance, which isn’t the scenario here.

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