A transmitter delivers 200 volts peak-to-peak across a 50-ohm load. What is the output peak envelope power?

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Multiple Choice

A transmitter delivers 200 volts peak-to-peak across a 50-ohm load. What is the output peak envelope power?

Power in a resistive load is determined by the RMS (not peak) voltage for a sinusoidal signal. A 200 V peak-to-peak sine has a peak voltage of 100 V. The RMS value of a sine with that peak is 100 / √2 ≈ 70.7 V. The power delivered to a 50-ohm load is P = Vrms^2 / R = (70.7^2) / 50 ≈ 5000 / 50 = 100 watts. So the output peak envelope power is about 100 W.

Power in a resistive load is determined by the RMS (not peak) voltage for a sinusoidal signal. A 200 V peak-to-peak sine has a peak voltage of 100 V. The RMS value of a sine with that peak is 100 / √2 ≈ 70.7 V. The power delivered to a 50-ohm load is P = Vrms^2 / R = (70.7^2) / 50 ≈ 5000 / 50 = 100 watts. So the output peak envelope power is about 100 W.

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